You connect three capacitors as shown in the diagram. C₁ = 5.0 μF, C₂ = 4.0 μF, and C₃ = 3.0 μF. If you apply 12-V between points A and B, the energy stored in C₃ will be approximately

Question

Quizplus · Accepted Answer

The energy stored in a capacitor is given by the formula: E = 1/2 * C * V^2 where E is the energy, C is the capacitance, and V is the voltage. In this circuit, the capacitors are in series, so the total capacitance is: Ct = 1/(1/C1 + 1/C2 + 1/C3) Plugging in the values, we get: Ct = 1/(1/5 + 1/4 + 1/3) = 60/31 μF The voltage across the capacitors is 12V, since they are in series. Now we can calculate the energy stored in C₃: E = 1/2 * 3.0 μF * (12V)^2 / (60/31 μF) = 0.118 mJ Therefore, the closest answer is C - 0.12 mJ.

You Connect Three Capacitors as Shown in the Diagram