The mean of the exponential distribution equals the mean of the Poisson distribution only when the former distribution has a mean equal to: $\begin{array}{|l|l|}
\hline\text { A. } & 1.0 . \
\hline \text { B. } & 0.50 \
\hline \text { C. } & 0.25 . \
\hline \text { D. } & \text { any value smaller than } 1.0 \
\hline
\end{array}$

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The Answer of The mean of the exponential distribution equals the mean of the Poisson distribution only when the former distribution has a mean equal to: $\begin{array}{|l|l|}
\hline\text { A. } & 1.0 . \
\hline \text { B. } & 0.50 \
\hline \text { C. } & 0.25 . \
\hline \text { D. } & \text { any value smaller than } 1.0 \
\hline
\end{array}$

The Mean of the Exponential Distribution Equals the Mean of the Poisson