A 3.0 . 10² kg black bear hibernates in the winter.During hibernation, the bear's body temperature drops from 37.0 to 31.0 $\degree$ C.About how many grams of glucose must the bear metabolize to restore its body temperature to normal? Assume the bear's body is mostly water with a specific heat capacity of 4.18 J/(g . $\degree$ C) and that all the energy from the combustion of glucose is used to raise the bear's body temperature.(Glucose: $\Delta$ H_comb =-2808 kJ/mol, molar mass = 180 g/mol)
C₆ H₁₂ O₆ (g) + 6O₂ (g) $\rightarrow$ 6 CO₂ (g) + 6H₂ O(l)

Question

A 3.0 . 10² kg black bear hibernates in the winter.During hibernation, the bear's body temperature drops from 37.0 to 31.0

\degree

C.About how many grams of glucose must the bear metabolize to restore its body temperature to normal? Assume the bear's body is mostly water with a specific heat capacity of 4.18 J/(g .

\degree

C) and that all the energy from the combustion of glucose is used to raise the bear's body temperature.(Glucose:

\Delta

H_comb =-2808 kJ/mol, molar mass = 180 g/mol)
C₆ H₁₂ O₆ (g) + 6O₂ (g)

\rightarrow

6 CO₂ (g) + 6H₂ O(l)

Quizplus · Accepted Answer

To calculate the amount of glucose needed, first find the energy required to raise the bear's body temperature using Q = mcΔT. Then, convert this energy to moles of glucose using the enthalpy of combustion, and finally convert moles to grams using the molar mass of glucose.

A 30 102 Kg Black Bear Hibernates in the Winter °\degree°

A 30 10² Kg Black Bear Hibernates in the Winter $\degree$