The reaction CHCl₃(g) +CL₂(g) $\degree$ CCL₄(g) + HCl(g) has the following rate law: Rate =k[CHCl₃][Cl₂].If the concentration of CHCl₃ is increased by a factor of five while the concentration of Cl₂ is kept the same, the rate will

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The rate law is given as Rate = k[CHCl3][Cl2], indicating that the rate is directly proportional to the concentration of CHCl3. Therefore, if the concentration of CHCl3 is increased by a factor of five, the rate will also increase by a factor of five, assuming the concentration of Cl2 remains constant.

The Reaction CHCl3(g) +CL2(g) °\degree° CCL4(g) + HCl(g) Has the Following Rate Law: Rate =K[CHCl3][Cl2]

The Reaction CHCl₃(g) +CL₂(g) $\degree$ CCL₄(g) + HCl(g) Has the Following Rate Law: Rate =K[CHCl₃][Cl₂]