A 25.00 mL sample of a hydrochloric acid solution was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide.What was the concentration of the hydrochloric acid?

Question

Quizplus · Accepted Answer

The concentration of the hydrochloric acid (HCl) can be found using the titration formula: $M_1V_1 = M_2V_2$, where $M_1$ and $M_2$ are the molarities of the acid and base, respectively, and $V_1$ and $V_2$ are the volumes of the acid and base, respectively. Given that $M_2 = 0.1020 \, M$ and $V_2 = 34.55 \, mL$, and $V_1 = 25.00 \, mL$, we can solve for $M_1$:$$M_1 = \frac{M_2V_2}{V_1} = \frac{0.1020 \, M \times 34.55 \, mL}{25.00 \, mL} = 0.1410 \, M.$$This calculation assumes a 1:1 molar reaction between HCl and NaOH, which is valid for these reactants.

A 2500 ML Sample of a Hydrochloric Acid Solution Was Titrated