The solubility of PbBr2 is 0.427 g per 100.0 mL of solution at 25°C.Determine the value of the solubility product constant for this strong electrolyte.Lead(II) bromide does not react with water.
A) 5.4 * 10-4
B) 2.7 * 10-4
C) 1.6 * 10-6
D) 3.1 *10-6
E) 6.3* 10-6
Correct Answer:
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