Let $ { \vec { F } } = 2 x \vec { i } + z \vec { j } + ( y + 2 x ) \vec { k }$ Use Stokes' Theorem to find $\dot { \mathrm { Q } } { \vec { F } \times \vec { d r } }$ where C is a circle in the xy-plane of radius $4$ , centered at $( 3,1,0 )$ oriented counter-clockwise when viewed from above.

Question

Let $  { \vec { F } } = 2 x \vec { i } + z \vec { j } + ( y + 2 x ) \vec { k }$ Use Stokes' Theorem to find $\dot { \mathrm { Q } }   { \vec { F } \times \vec { d r } }$ where C is a circle in the xy-plane of radius $4$ , centered at $( 3,1,0 )$ oriented counter-clockwise when viewed from above.

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The Answer of Let $  { \vec { F } } = 2 x \vec { i } + z \vec { j } + ( y + 2 x ) \vec { k }$ Use Stokes' Theorem to find $\dot { \mathrm { Q } }   { \vec { F } \times \vec { d r } }$ where C is a circle in the xy-plane of radius $4$ , centered at $( 3,1,0 )$ oriented counter-clockwise when viewed from above.

Let F⃗=2xi⃗+zj⃗+(y+2x)k⃗ { \vec { F } } = 2 x \vec { i } + z \vec { j } + ( y + 2 x ) \vec { k }F=2xi+zj​+(y+2x)k

Let ${ \vec { F } } = 2 x \vec { i } + z \vec { j } + ( y + 2 x ) \vec { k }$