Let $\vec { G }$ be a smooth vector field with $\operatorname { div } \vec { G } = 3$ at every point in space.Find the exponent p in the following: $\frac { \text { The flux of } \vec { G } \text { out of any sphere of radius } r _ { 1 } } { \text { The flux of } \vec { G } \text { out of any sphere of radius } r _ { 2 } } = \left( \frac { r _ { 1 } } { r _ { 2 } } \right) ^ { p }$

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The Answer of Let $\vec { G }$ be a smooth vector field with $\operatorname { div } \vec { G } = 3$ at every point in space.Find the exponent p in the following: $\frac { \text { The flux of } \vec { G } \text { out of any sphere of radius } r _ { 1 } } { \text { The flux of } \vec { G } \text { out of any sphere of radius } r _ { 2 } } = \left( \frac { r _ { 1 } } { r _ { 2 } } \right) ^ { p }$

Let G⃗\vec { G }G Be a Smooth Vector Field With div⁡G⃗=3\operatorname { div } \vec { G } = 3divG=3

Let $\vec { G }$ Be a Smooth Vector Field With $\operatorname { div } \vec { G } = 3$