A child is sliding down a helical slide.Her position at time t after the start is given in feet by $\vec { r } = \cos t \vec { i } + \sin t \vec { j } + ( 12 - t ) \vec { k }$ .The ground is the xy-plane.
At time t = 2 $\pi$, the child leaves the slide on the tangent to the slide at that point.What is the equation of the tangent line?

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The Answer of A child is sliding down a helical slide.Her position at time t after the start is given in feet by $\vec { r } = \cos t \vec { i } + \sin t \vec { j } + ( 12 - t ) \vec { k }$ .The ground is the xy-plane.
At time t = 2 $\pi$, the child leaves the slide on the tangent to the slide at that point.What is the equation of the tangent line?

A Child Is Sliding Down a Helical Slide r⃗=cos⁡ti⃗+sin⁡tj⃗+(12−t)k⃗\vec { r } = \cos t \vec { i } + \sin t \vec { j } + ( 12 - t ) \vec { k }r=costi+sintj​+(12−t)k

A Child Is Sliding Down a Helical Slide $\vec { r } = \cos t \vec { i } + \sin t \vec { j } + ( 12 - t ) \vec { k }$