Consider the curve $\vec { r } ( t ) = \left( 5 t ^ { 2 } + 1 \right) \vec { i } + \left( t ^ { 2 } - 5 \right) \vec { j } + t \vec { k }$ Find the equation of the tangent line at the point where t = 2.

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The Answer of Consider the curve $\vec { r } ( t ) = \left( 5 t ^ { 2 } + 1 \right) \vec { i } + \left( t ^ { 2 } - 5 \right) \vec { j } + t \vec { k }$ Find the equation of the tangent line at the point where t = 2.

Consider the Curve r⃗(t)=(5t2+1)i⃗+(t2−5)j⃗+tk⃗\vec { r } ( t ) = \left( 5 t ^ { 2 } + 1 \right) \vec { i } + \left( t ^ { 2 } - 5 \right) \vec { j } + t \vec { k }r(t)=(5t2+1)i+(t2−5)j​+tk

Consider the Curve $\vec { r } ( t ) = \left( 5 t ^ { 2 } + 1 \right) \vec { i } + \left( t ^ { 2 } - 5 \right) \vec { j } + t \vec { k }$