If a function z = g(x, y)has g(1, 2)= -5, g_x(1, 2)= 4 and g_y(1, 2)= 3, find the equation of the plane tangent to the surface z = g(x, y)at the point where x = 1 and y = 2.

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The Answer of If a function z = g(x, y)has g(1, 2)= -5, g_x(1, 2)= 4 and g_y(1, 2)= 3, find the equation of the plane tangent to the surface z = g(x, y)at the point where x = 1 and y = 2.

If a Function Z = G(x, Y)has G(1, 2)= -5