Let $z = \ln \left( x ^ { 2 } + 2 x y + 2 y \right) , x = t ^ { 2 } + 3 , y = t + \sqrt { t }$ Find dz/dt at t = 1 using the chain rule.Give your answer to 4 decimal places.

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The Answer of Let $z = \ln \left( x ^ { 2 } + 2 x y + 2 y \right) , x = t ^ { 2 } + 3 , y = t + \sqrt { t }$ Find dz/dt at t = 1 using the chain rule.Give your answer to 4 decimal places.

Let z=ln⁡(x2+2xy+2y),x=t2+3,y=t+tz = \ln \left( x ^ { 2 } + 2 x y + 2 y \right) , x = t ^ { 2 } + 3 , y = t + \sqrt { t }z=ln(x2+2xy+2y),x=t2+3,y=t+t​

Let $z = \ln \left( x ^ { 2 } + 2 x y + 2 y \right) , x = t ^ { 2 } + 3 , y = t + \sqrt { t }$