Is the Taylor polynomial of degree 6 for $e^{-x^{2}}$ for x near 0 given by $1+\frac{x^{2}}{2 !}+\frac{x^{4}}{4 !}+\frac{x^{6}}{6 !}$ ?

Name: Is the Taylor polynomial of degree 6 for $e^{-x^{2}}$ for x near 0 given by $1+\frac{x^{2}}{2 !}+\frac{x^{4}}{4 !}+\frac{x^{6}}{6 !}$ ?
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The Answer of Is the Taylor polynomial of degree 6 for $e^{-x^{2}}$ for x near 0 given by $1+\frac{x^{2}}{2 !}+\frac{x^{4}}{4 !}+\frac{x^{6}}{6 !}$ ?

Is the Taylor Polynomial of Degree 6 For e−x2e^{-x^{2}}e−x2 For X near 0 Given By

Is the Taylor Polynomial of Degree 6 For $e^{-x^{2}}$ For X near 0 Given By