$\int 7 x \ln x d x=\frac{7}{2} x^{2} \ln x+C$ .

Name: $\int 7 x \ln x d x=\frac{7}{2} x^{2} \ln x+C$ .
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Question

Quizplus · Accepted Answer

The correct integral of $7x \ln x dx$ involves integration by parts and results in $\frac{7}{2} x^2 \ln x - \frac{7}{4} x^2 + C$, not just $\frac{7}{2} x^2 \ln x + C$.

∫7xln⁡xdx=72x2ln⁡x+C\int 7 x \ln x d x=\frac{7}{2} x^{2} \ln x+C∫7xlnxdx=27​x2lnx+C

$\int 7 x \ln x d x=\frac{7}{2} x^{2} \ln x+C$