Is the function $\frac{1}{\sqrt{x^{2}-9}}$
continuous on the interval $0 \leq x \leq 4$
?

Name: Is the function $\frac{1}{\sqrt{x^{2}-9}}$ continuous on the interval $0 \leq x \leq 4$ ?
Brand: Quizplus
Rating: 4.8 (39 reviews)

Question

Is the function $\frac{1}{\sqrt{x^{2}-9}}$
 continuous on the interval $0 \leq x \leq 4$
 ?

Quizplus · Accepted Answer

The function $\frac{1}{\sqrt{x^{2}-9}}$ is not defined for $x < 3$ because the expression under the square root, $x^{2}-9$, is negative, making the square root undefined for real numbers. Therefore, it cannot be continuous on the interval $0 \leq x \leq 4$ since it is not even defined for $0 \leq x < 3$.

Is the Function 1x2−9\frac{1}{\sqrt{x^{2}-9}}x2−9​1​ Continuous on the Interval 0≤x≤40 \leq x \leq 40≤x≤4

Is the Function $\frac{1}{\sqrt{x^{2}-9}}$ Continuous on the Interval $0 \leq x \leq 4$