During the 2013 Major League Baseball season, the St. Louis Cardinals averaged 41,602 fans per home game. Suppose attendance during the season follows the normal probability distribution with a standard deviation of 9,440 per game. What is the probability that a randomly selected game during the 2013 season had an attendance fewer than than 55,000 people?

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To find the probability, we use the z-score formula: z = (X - μ) / σ, where X is the value in question (55,000), μ is the mean (41,602), and σ is the standard deviation (9,440). Plugging in the values gives z = (55,000 - 41,602) / 9,440 ≈ 1.42. Looking up 1.42 on the standard normal distribution table gives a value of approximately 0.9222, indicating that the probability of a randomly selected game having fewer than 55,000 people is about 92.22%.

During the 2013 Major League Baseball Season, the St