Solve the problem.
-A sample of $900 \mathrm {~g}$ of lead-210 decays to polonium-210 according to the function given by $\mathrm { A } ( \mathrm { t } ) = 900 \mathrm { e } ^ { - 0.032 \mathrm { t } }$, where $t$ is time in years. What is the amount of the sample after 50 years (to the nearest g)?
A) $182 \mathrm {~g}$
B) $132 \mathrm {~g}$
C) $4458 \mathrm {~g}$
D) $28 \mathrm {~g}$

Question

Quizplus · Accepted Answer

To find the amount of the sample after 50 years, substitute $t = 50$ into the given function: $A(50) = 900e^{-0.032 \times 50}$. Calculating this gives approximately $182 \mathrm {~g}$.

Solve the Problem 900 g900 \mathrm {~g}900 g Of Lead-210 Decays to Polonium-210 According to the Function Given

Solve the Problem $900 \mathrm {~g}$ Of Lead-210 Decays to Polonium-210 According to the Function Given