Evaluate the function at the given value of the independent variable and simplify.
-$$f ( x ) = \frac { x ^ { 3 } + 3 } { x ^ { 2 } - 5 } ; \quad f ( 5 )$$
A) $\frac { 128 } { 25 }$
B) $\frac { 32 } { 5 }$
C) $\frac { 7 } { 5 }$
D) $\frac { 25 } { 4 }$

Question

Quizplus · Accepted Answer

To evaluate $f(5)$, substitute $x = 5$ into the function: $f(5) = \frac{5^3 + 3}{5^2 - 5} = \frac{125 + 3}{25 - 5} = \frac{128}{20} = \frac{32}{5}$.

Evaluate the Function at the Given Value of the Independent f(x)=x3+3x2−5;f(5)f ( x ) = \frac { x ^ { 3 } + 3 } { x ^ { 2 } - 5 } ; \quad f ( 5 )f(x)=x2−5x3+3​;f(5)

Evaluate the Function at the Given Value of the Independent $f ( x ) = \frac { x ^ { 3 } + 3 } { x ^ { 2 } - 5 } ; \quad f ( 5 )$