Solve
-A rocket is stopped 25 feet from a satellite when it begins accelerating away from the satellite at a constant rate of 14 feet per second per second. The distance between the rocket and the satellite is given by the polynomial $7 t ^ { 2 }$ $+ 25$. Find the distance between the rocket and the satellite 9 seconds after the rocket started moving.
A) 106 feet
B) 592 feet
C) 88 feet
D) 567 feet

Question

Quizplus · Accepted Answer

The distance between the rocket and the satellite after 9 seconds can be calculated by substituting $t = 9$ into the given polynomial $7t^2 + 25$. This gives $7(9)^2 + 25 = 7(81) + 25 = 567 + 25 = 592$ feet.

Solve -A Rocket Is Stopped 25 Feet from a Satellite 7t27 t ^ { 2 }7t2

Solve
-A Rocket Is Stopped 25 Feet from a Satellite $7 t ^ { 2 }$