Solve the problem.
-$$\left( x + \frac { 6 } { 7 } \right) \left( x - \frac { 5 } { 7 } \right)$$
A) $x ^ { 2 } + \frac { 1 } { 7 } x - \frac { 30 } { 49 }$
B) $x ^ { 2 } + \frac { 11 } { 7 } x - \frac { 30 } { 49 }$
C) $x ^ { 2 } + \frac { 37 } { 49 } x + \frac { 1 } { 49 }$
D) $x ^ { 2 } + \frac { 37 } { 49 } x - \frac { 30 } { 49 }$

Question

Quizplus · Accepted Answer

This is a multiplication of two binomials. Using the FOIL method (First, Outer, Inner, Last), we get:First: $x \cdot x = x^2$Outer: $x \cdot -\frac{5}{7} = -\frac{5}{7}x$Inner: $\frac{6}{7} \cdot x = \frac{6}{7}x$Last: $\frac{6}{7} \cdot -\frac{5}{7} = -\frac{30}{49}$Adding these together: $x^2 + \left(-\frac{5}{7} + \frac{6}{7}\right)x - \frac{30}{49}$Simplifies to: $x^2 + \frac{1}{7}x - \frac{30}{49}$

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Solve the Problem $\left( x + \frac { 6 } { 7 } \right) \left( x - \frac { 5 } { 7 } \right)$