Evaluate.
-$2 ^ { \log _ { 2 } 13 }$

Name: Evaluate. -$2 ^ { \log _ { 2 } 13 }$
Brand: Quizplus
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Question

Quizplus · Accepted Answer

The expression $2 ^ { \log _ { 2 } 13 }$ simplifies directly to 13 because the base of the exponent (2) and the base of the logarithm (2) are the same, which means they cancel each other out, leaving the argument of the logarithm (13) as the result.

Evaluate - 2log⁡2132 ^ { \log _ { 2 } 13 }2log2​13

Evaluate
- $2 ^ { \log _ { 2 } 13 }$