A stepped steel shaft (G = 75 GPa) with diameters $d_{1}=36 \mathrm{~mm}$ and $d_{2}=32 \mathrm{~mm}$ is twisted by torques T at each end. Segment lengths are $L_{1}=0.9 \mathrm{~m} \text { and } L_{2}=0.75 \mathrm{~m} \text {. }$ . If the allowable shear stress is 28 MPa and maximum allowable twist is 1.8 °, the maximum permissible torque is
Approximately:

Question

Quizplus · Accepted Answer

The maximum permissible torque is determined by the lesser of the two limits: allowable shear stress and maximum allowable twist. Calculating for both and choosing the smaller torque ensures the shaft's integrity.

A Stepped Steel Shaft (G = 75 GPa) with Diameters d1=36 mmd_{1}=36 \mathrm{~mm}d1​=36 mm

A Stepped Steel Shaft (G = 75 GPa) with Diameters $d_{1}=36 \mathrm{~mm}$