The following MINITAB output presents a confidence interval for a population mean.
$\begin{array}{crrrcc}
\hline \text { Variable } & \mathrm{N} & \text { Mean } & \text { StDev } & \text { SE Mean } & 99 \% \mathrm{CI} \
\mathrm{x} & 62 & 97.2259 & 34.3638 & 4.3642 & (85.622,108.830) \
\hline
\end{array}$
How many degrees of freedom are there?
A) 62
B) $4.3642$
C) 63
D) 61

Question

Quizplus · Accepted Answer

The degrees of freedom for a confidence interval for a population mean is calculated as $N - 1$, where $N$ is the sample size. Here, $N = 62$, so the degrees of freedom are $62 - 1 = 61$.

The Following MINITAB Output Presents a Confidence Interval for a Population