Find the margin of error for the given confidence level and values of x and n . x=79, n=187 , confidence level 98%
A) 0.08402
B) 0.4225
C) 0.03612
D) 0.5775

Question

Find the margin of error for the given confidence level and values of  x  and  n .  x=79, n=187 , confidence level  98% 
A)  0.08402 
B)  0.4225 
C)  0.03612 
D)  0.5775

Quizplus · Accepted Answer

The margin of error is given by:ME = z * sqrt((p(1-p))/n)where z is the z-score corresponding to the confidence level, p is the sample proportion, and n is the sample size.For a 98% confidence level, z = 2.326. The sample proportion is p = x/n = 79/187 = 0.4225. Therefore, the margin of error is:ME = 2.326 * sqrt((0.4225(1-0.4225))/187) = 0.08402Therefore, the correct choice is A.

Find the Margin of Error for the Given Confidence Level