The following MINITAB output display presents a 95% confidence interval for the difference between two means.
$\begin{array} { l r r r c } & \mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \ \text { A } & 14 & 136.895 & 22.382 & 5.982 \ \text { B } & 10 & 115.675 & 27.816 & 8.796 \end{array}$
Difference $= m u ( A ) - m u ( B )$
Estimate for difference: $\quad 21.220$

How many degrees of freedom did MINITAB use?
A) $41.698$
B) 24
C) 17
D) $21.22$

Question

The following MINITAB output display presents a 95% confidence interval for the difference between two means.
 $\begin{array} { l r r r c } & \mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \ \text { A } & 14 & 136.895 & 22.382 & 5.982 \ \text { B } & 10 & 115.675 & 27.816 & 8.796 \end{array}$
Difference $= m u ( A ) - m u ( B )$
Estimate for difference: $\quad 21.220$

How many degrees of freedom did MINITAB use?
A) $41.698$ 
B) 24 
C) 17 
D) $21.22$

Quizplus · Accepted Answer

The Answer of The following MINITAB output display presents a 95% confidence interval for the difference between two means.
 $\begin{array} { l r r r c } & \mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \ \text { A } & 14 & 136.895 & 22.382 & 5.982 \ \text { B } & 10 & 115.675 & 27.816 & 8.796 \end{array}$
Difference $= m u ( A ) - m u ( B )$
Estimate for difference: $\quad 21.220$

How many degrees of freedom did MINITAB use?
A) $41.698$ 
B) 24 
C) 17 
D) $21.22$

The Following MINITAB Output Display Presents a 95% Confidence Interval