The 95% confidence interval for the predicted effect of a general change in X is a. $\quad \left( \beta _ { 1 } \Delta x - 1.96 \operatorname { SE } \left( \beta _ { 1 } \right) \times \Delta x , \beta _ { 1 } \Delta x + 1.96 \operatorname { SE } \left( \beta _ { 1 } \right) \times \Delta x \right)$
b. $\left( \widehat { \beta } _ { 1 } \Delta x - 1.645 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x , \widehat { \beta } _ { 1 } \Delta x + 1.645 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x \right)$
c. $\left( \hat { \beta } _ { 1 } \Delta x - 1.96 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x , \widehat { \beta } _ { 1 } \Delta x + 1.96 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x \right)$
d. $\left( \widehat { \beta } _ { 1 } \Delta x - 1.96 , \widehat { \beta } _ { 1 } \Delta x + 1.96 \right)$

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The Answer of The 95% confidence interval for the predicted effect of a general change in X is a. $\quad \left( \beta _ { 1 } \Delta x - 1.96 \operatorname { SE } \left( \beta _ { 1 } \right) \times \Delta x , \beta _ { 1 } \Delta x + 1.96 \operatorname { SE } \left( \beta _ { 1 } \right) \times \Delta x \right)$
b. $\left( \widehat { \beta } _ { 1 } \Delta x - 1.645 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x , \widehat { \beta } _ { 1 } \Delta x + 1.645 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x \right)$
c. $\left( \hat { \beta } _ { 1 } \Delta x - 1.96 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x , \widehat { \beta } _ { 1 } \Delta x + 1.96 \operatorname { SE } \left( \hat { \beta } _ { 1 } \right) \times \Delta x \right)$
d. $\left( \widehat { \beta } _ { 1 } \Delta x - 1.96 , \widehat { \beta } _ { 1 } \Delta x + 1.96 \right)$

The 95% Confidence Interval for the Predicted Effect of a General