A researcher at a major clinic wishes to estimate the proportion of the adult population of the United States thathas sleep deprivation. How large a sample is needed in order to be 95% confident that the sample proportionwill not differ from the true proportion by more than 4%?
A) 601
B) 13
C) 1201
D) 423

Question

Quizplus · Accepted Answer

The sample size needed is given by the formula n = (Z^2 * p * q) / e^2, where Z is the z-score for the desired confidence level, p is the estimated proportion, q is 1 - p, and e is the margin of error. Plugging in the values given in the question, we get n = (1.96^2 * 0.5 * 0.5) / 0.04^2 = 600.25. Rounding up to the nearest whole number, we get a sample size of 601.

A Researcher at a Major Clinic Wishes to Estimate the Proportion