On a recent day during the flu season, the Midtown Medical Clinic saw many patients. Patients had theirtemperatures (in °F) taken. The distribution of temperatures is given below. Determine the mean temperatureof a sample of 100 patients. $$\begin{array} { | c | c | }
\hline \text { Temperatures } & \text { Frequency } \
\hline 95.6 - 96.49 & 1 \
\hline 96.5 - 97.39 & 3 \
\hline 97.4 - 98.29 & 19 \
\hline 98.3 - 99.19 & 28 \
\hline 99.2 - 100.09 & 35 \
\hline 100.1 - 100.99 & 12 \
\hline 101.0 - 101.89 & 2 \
\hline
\end{array}$$
A) 99.08°F
B) 99.52°F
C) 98.75°F
D) 98.63°F

Question

On a recent day during the flu season, the Midtown Medical Clinic saw many patients. Patients had theirtemperatures (in °F) taken. The distribution of temperatures is given below. Determine the mean temperatureof a sample of 100 patients. $$\begin{array} { | c | c | } 
\hline \text { Temperatures } & \text { Frequency } \
\hline 95.6 - 96.49 & 1 \
\hline 96.5 - 97.39 & 3 \
\hline 97.4 - 98.29 & 19 \
\hline 98.3 - 99.19 & 28 \
\hline 99.2 - 100.09 & 35 \
\hline 100.1 - 100.99 & 12 \
\hline 101.0 - 101.89 & 2 \
\hline
\end{array}$$
A) 99.08°F
B) 99.52°F
C) 98.75°F
D) 98.63°F

Quizplus · Accepted Answer

To find the mean temperature, we calculate the midpoint of each temperature range and multiply it by the frequency of that range, then sum these products and divide by the total number of patients (100). The calculation is as follows:- For 95.6 - 96.49, midpoint is 96.045, frequency is 1, so 96.045 * 1 = 96.045- For 96.5 - 97.39, midpoint is 96.945, frequency is 3, so 96.945 * 3 = 290.835- For 97.4 - 98.29, midpoint is 97.845, frequency is 19, so 97.845 * 19 = 1859.055- For 98.3 - 99.19, midpoint is 98.745, frequency is 28, so 98.745 * 28 = 2764.86- For 99.2 - 100.09, midpoint is 99.645, frequency is 35, so 99.645 * 35 = 3487.575- For 100.1 - 100.99, midpoint is 100.545, frequency is 12, so 100.545 * 12 = 1206.54- For 101.0 - 101.89, midpoint is 101.445, frequency is 2, so 101.445 * 2 = 202.89Adding these products gives a total of 9907.8. Dividing by the total number of patients (100) gives a mean temperature of 99.078°F, which rounds to 99.08°F.

On a Recent Day During the Flu Season, the Midtown