A television station claims that the amount of advertising per hour of broadcast time has an average of 16minutes and a standard deviation equal to 1.4 minutes. You watch the station for 1 hour, at a randomlyselected time, and carefully observe that the amount of advertising time is equal to 8 minutes. Calculate thez-score for this amount of advertising time.
A) z = -5.71
B) z = 5.71
C) z = -0.41
D) z = 0.41

Question

Quizplus · Accepted Answer

The z-score is calculated using the formula $z = \frac{(X - \mu)}{\sigma}$, where $X$ is the observed value, $\mu$ is the mean, and $\sigma$ is the standard deviation. Plugging in the given values: $z = \frac{(8 - 16)}{1.4} = \frac{-8}{1.4} = -5.71$.

A Television Station Claims That the Amount of Advertising Per