Solve the problem.
-Maha checked the outside temperature at noon one day and found it was 28° C. At 10 PM when he Checked, the outside temperature was 17° C. How much, in degrees Fahrenheit, did the Temperature drop between noon and 10 PM?
A) -12.2°F
B) 19.8°F
C) -7.2°F
D) 6.11°F

Question

Quizplus · Accepted Answer

To find the temperature drop in Fahrenheit, first convert the temperatures from Celsius to Fahrenheit using the formula F = (C × 9/5) + 32. The noon temperature is 28°C, which is 82.4°F, and the 10 PM temperature is 17°C, which is 62.6°F. The drop is 82.4°F - 62.6°F = 19.8°F.

Solve the Problem. -Maha Checked the Outside Temperature at Noon One Day and One