Given p is true, q is true, and r is false, find the truth value of the statement.
-$$[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }$$

Question

Quizplus · Accepted Answer

The statement $( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } )$ simplifies to False $\wedge$ True, which is False. Therefore, False $\rightarrow$ r (False) is True, contradicting the final statement's implication towards r being True.

Given P Is True, Q Is True, and R Is [(∼p→r)∧(∼p∨q)]→r[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }[(∼p→r)∧(∼p∨q)]→r

Given P Is True, Q Is True, and R Is $[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }$