Solve the problem.
-How many different three-number ʺcombinationsʺ are possible on a combination lock having 22 Numbers on its dial? Assume that no numbers repeat. (Combination locks are really permutation Locks.)
A) 9240
B) 1,053,400
C) 351,120
D) 175,560

Question

Quizplus · Accepted Answer

The total number of different three-number combinations (permutations, since order matters) possible on a combination lock with 22 numbers, assuming no repeats, is calculated using the permutation formula P(n, r) = n! / (n-r)!, where n is the total number of options (22) and r is the number of selections (3). Thus, P(22, 3) = 22! / (22-3)! = 22! / 19! = 22 x 21 x 20 = 9240.

Solve the Problem. -How Many Different Three-Number ʺCombinationsʺ Are Possible on a Combination