Solve the problem.
-If the police have 8 suspects, how many different ways can they select 5 for a lineup?
A) 336
B) 40
C) 6720
D) 56

Question

Quizplus · Accepted Answer

The number of ways to select 5 suspects out of 8 for a lineup is calculated using the combination formula, which is $C(n, k) = \frac{n!}{k!(n-k)!}$. Here, $n=8$ and $k=5$, so $C(8, 5) = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56$.

Solve the Problem. -If the Police Have 8 Suspects, How Many Different Ways