Factor completely. -2x²- 2x - 12 A) 2(x - 2)(x + 3) B) 2(x + 2)(x - 3) C) (2x + 4)(x - 3) D) prime

Name: Factor completely. -2x 2 - 2x - 12 A) 2(x - 2)(x + 3) B) 2(x + 2)(x - 3) C) (2x + 4)(x - 3) D) prime
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Question

Quizplus · Accepted Answer

The expression 2x^2 - 2x - 12 can be factored by first taking out the common factor of 2, resulting in 2(x^2 - x - 6). The quadratic x^2 - x - 6 can be factored further into (x + 2)(x - 3). Therefore, the complete factorization is 2(x + 2)(x - 3).

Factor Completely. -2x2- 2x - 12

Factor Completely. -2x²- 2x - 12