Factor completely using the trial and error method to factor trinomials. If unfactorable, indicate that the polynomial is
prime.
-$$6 x ^ { 2 } - 21 x - 12$$
A) $3 ( 2 x - 1 ) ( x + 4 )$
B) $3 ( 2 x + 1 ) ( x - 4 )$
C) prime
D) $( 6 x - 3 ) ( x + 4 )$

Question

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The Answer of Factor completely using the trial and error method to factor trinomials. If unfactorable, indicate that the polynomial is
prime.
-$$6 x ^ { 2 } - 21 x - 12$$
A) $3 ( 2 x - 1 ) ( x + 4 )$
B) $3 ( 2 x + 1 ) ( x - 4 )$
C) prime
D) $( 6 x - 3 ) ( x + 4 )$

Factor Completely Using the Trial and Error Method to Factor 6x2−21x−126 x ^ { 2 } - 21 x - 126x2−21x−12

Factor Completely Using the Trial and Error Method to Factor $6 x ^ { 2 } - 21 x - 12$