Solve the problem.
-Molly has $12.45 in coins. She has four more nickels than dimes. She has seven fewer quarters than dimes. How many quarters does she have?
A) 32 quarters
B) 35 quarters
C) 39 quarters
D) 28 quarters

Question

Quizplus · Accepted Answer

Molly's total amount in coins is $12.45. Let's denote the number of dimes as $d$, the number of nickels as $n$, and the number of quarters as $q$. According to the problem, we have:1. $n = d + 4$ (four more nickels than dimes)2. $q = d - 7$ (seven fewer quarters than dimes)The value of the coins can be represented as:- Nickels: $0.05n$- Dimes: $0.10d$- Quarters: $0.25q$The total amount can be represented as:$$0.05n + 0.10d + 0.25q = 12.45$$Substituting $n$ and $q$ from the given relationships:$$0.05(d + 4) + 0.10d + 0.25(d - 7) = 12.45$$Simplifying:$$0.05d + 0.20 + 0.10d + 0.25d - 1.75 = 12.45$$Combining like terms:$$0.40d - 1.55 = 12.45$$Solving for $d$:$$0.40d = 14.00$$$$d = 35$$Substituting $d = 35$ into $q = d - 7$:$$q = 35 - 7 = 28$$Therefore, Molly has 28 quarters.

Solve the Problem. -Molly Has $12.45 in Coins. She Has Four More Nickels