Solve the equation. Use words or set notation to identify equations that have no solution, or equations that are true for all
real numbers.
-$$\frac { 1 } { 3 } ( 6 x - 9 ) = 6 \left( \frac { 1 } { 3 } x - \frac { 1 } { 2 } \right) + 8$$
A) $\{ 0 \}$
B) $\{ x \mid x$ is a real number $\}$
C) $\{ varnothing \}$
D) $\{ 2 \}$

Question

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The Answer of Solve the equation. Use words or set notation to identify equations that have no solution, or equations that are true for all
real numbers.
-$$\frac { 1 } { 3 } ( 6 x - 9 ) = 6 \left( \frac { 1 } { 3 } x - \frac { 1 } { 2 } \right) + 8$$
A) $\{ 0 \}$
B) $\{ x \mid x$ is a real number $\}$
C) $\{ varnothing \}$
D) $\{ 2 \}$

Solve the Equation 13(6x−9)=6(13x−12)+8\frac { 1 } { 3 } ( 6 x - 9 ) = 6 \left( \frac { 1 } { 3 } x - \frac { 1 } { 2 } \right) + 831​(6x−9)=6(31​x−21​)+8

Solve the Equation $\frac { 1 } { 3 } ( 6 x - 9 ) = 6 \left( \frac { 1 } { 3 } x - \frac { 1 } { 2 } \right) + 8$