$\left\{ \begin{array} { l }
x ^ { 2 } - y ^ { 2 } = 39 \
x - y = 3
\end{array} \right.$
A) (8,-5)
B) (-8,5)
C) (8,5)
D) (-8,-5)

Question

$\left\{ \begin{array} { l } 
x ^ { 2 } - y ^ { 2 } = 39 \
x - y = 3
\end{array} \right.$
A)  (8,-5) 
B)  (-8,5) 
C)  (8,5) 
D)  (-8,-5)

Quizplus · Accepted Answer

Substitute the second equation into the first equation to get $x^2 - (x-3)^2 = 39$. Simplify to get $x^2 - x^2 + 6x - 9 = 39$. Simplify further to get $6x = 48$. Divide both sides by 6 to get $x = 8$. Substitute this value of $x$ back into the second equation to get $8 - y = 3$. Solve for $y$ to get $y = 5$. Therefore, the solution to the system of equations is $(8, 5)$.

{x2−y2=39x−y=3\left\{ \begin{array} { l } x ^ { 2 } - y ^ { 2 } = 39 \\x - y = 3\end{array} \right.{x2−y2=39x−y=3​

$\left\{ \begin{array} { l } x ^ { 2 } - y ^ { 2 } = 39 \\x - y = 3\end{array} \right.$