Solve the equation for y.
-Suppose the sales of a particular brand of appliance satisfy the relationship $S ( x ) = 80 x + 3600$, where $S ( x )$ represents the number of sales in year $x$, with $x = 0$ corresponding to 2010 . In what year would the sales be $4320 ?$
A) 2018
B) 2021
C) 2020
D) 2019

Question

Quizplus · Accepted Answer

To find the year when sales are 4320, set $S(x) = 4320$ and solve for $x$:  $4320 = 80x + 3600$  $720 = 80x$  $x = 9$  Since $x = 0$ corresponds to 2010, $x = 9$ corresponds to 2019.

Solve the Equation for Y S(x)=80x+3600S ( x ) = 80 x + 3600S(x)=80x+3600

Solve the Equation for Y $S ( x ) = 80 x + 3600$