Solve the problem.
-Bob fenced in a rectangular garden in his yard. The length of the rectangle is $7 \mathrm { ft }$ longer than the width and the perimeter is $122 \mathrm { ft }$. What is the width of the rectangle?
A) $29 \mathrm { ft }$
B) $26 \mathrm { ft }$
C) $27 \mathrm { ft }$
D) $54 \mathrm { ft }$

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by $2l + 2w$, where $l$ is the length and $w$ is the width. Given that the length is $7 \mathrm{ft}$ longer than the width ($l = w + 7$) and the perimeter is $122 \mathrm{ft}$, we can set up the equation $2(w + 7) + 2w = 122$. Solving for $w$, we find that the width is $27 \mathrm{ft}$.

Solve the Problem 7ft7 \mathrm { ft }7ft Longer Than the Width and the Perimeter Is

Solve the Problem $7 \mathrm { ft }$ Longer Than the Width and the Perimeter Is