Solve the equation.
-$$4 ^ { ( 7 + 3 x ) } = \frac { 1 } { 16 }$$
A) $\{ 4 \}$
B) $\left\{ \frac { 1 } { 4 } \right\}$
C) $\{ 3 \}$
D) $\{ - 3 \}$

Name: Solve the equation. -\[4 ^ { ( 7 + 3 x ) } = \frac { 1 } { 16 }\] A) $\{ 4 \}$ B) $\left\{ \frac { 1 } { 4 } \right\}$ C) $\{ 3 \}$ D) $\{ - 3 \}$
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Question

Quizplus · Accepted Answer

The equation can be rewritten as $4^{7+3x} = 4^{-2}$ because $16 = 4^2$ and $\frac{1}{16} = 4^{-2}$. Equating the exponents gives $7 + 3x = -2$. Solving for $x$ yields $x = -3$.

Solve the Equation 4(7+3x)=1164 ^ { ( 7 + 3 x ) } = \frac { 1 } { 16 }4(7+3x)=161​

Solve the Equation $4 ^ { ( 7 + 3 x ) } = \frac { 1 } { 16 }$