Solve Linear Systems by Addition
-$$\begin{array} { r }
6 x + 2 y = - 6 \
- 6 x - 9 y = 48
\end{array}$$
A) $\{ ( 1 , - 6 ) \}$
B) $\{ ( - 1,6 ) \}$
C) $\{ ( - 1 , - 6 ) \}$
D) $\varnothing$

Question

Solve Linear Systems by Addition
-$$\begin{array} { r } 
6 x + 2 y = - 6 \
- 6 x - 9 y = 48
\end{array}$$
A) $\{ ( 1 , - 6 ) \}$
B) $\{ ( - 1,6 ) \}$
C) $\{ ( - 1 , - 6 ) \}$
D) $\varnothing$

Quizplus · Accepted Answer

Adding the two equations eliminates the $x$-term and gives $-7y=42$, so $y=-6$. Substituting this value of $y$ into the first equation gives $6x+2(-6)=-6$, so $x=-1$. Therefore, the solution is $\{( - 1 , - 6 ) \}$.

Solve Linear Systems by Addition - 6x+2y=−6−6x−9y=48\begin{array} { r } 6 x + 2 y = - 6 \\- 6 x - 9 y = 48\end{array}6x+2y=−6−6x−9y=48​

Solve Linear Systems by Addition
- $\begin{array} { r } 6 x + 2 y = - 6 \\- 6 x - 9 y = 48\end{array}$