Use a graph in a [ $$\left[ - 2 \pi , 2 \pi , \frac { \pi } { 2 } \right] \text { by } [ - 3,3,1 ]$$ 3, 3, 1] viewing rectangle to complete the identity.
-$\frac { 1 - 2 \cos 2 x } { 2 \sin x - 1 } =$ ?
A) $2 \sin x + 1$
B) $2 \cos x + 1$
C) $\sin x + 1$
D) $\cos x - 1$

Question

Quizplus · Accepted Answer

The identity $\frac { 1 - 2 \cos 2 x } { 2 \sin x - 1 } = 2 \sin x + 1$ can be verified by transforming the left side of the equation or graphically analyzing the functions. The given range and interval suggest plotting both sides of the equation within the specified domain and comparing their graphs. The correct identity will show identical graphs for both sides of the equation over the given interval.

Use a Graph in a [ [−2π,2π,π2] by [−3,3,1]\left[ - 2 \pi , 2 \pi , \frac { \pi } { 2 } \right] \text { by } [ - 3,3,1 ][−2π,2π,2π​] by [−3,3,1]

Use a Graph in a [ $\left[ - 2 \pi , 2 \pi , \frac { \pi } { 2 } \right] \text { by } [ - 3,3,1 ]$