The model predicted $$\sqrt { \text { distance } } = 3.30 + 0.235 \times \text { speed }$$ can be used to predict the
Stopping distance (in feet) for a car traveling at a specific speed (in mph). According to
This model, about how much distance will a car going 65 mph need to stop?
A) 345.0 feet
B) 18.6 feet
C) 27.0 feet
D) 4.3 feet
E) 729.0 feet

Question

Quizplus · Accepted Answer

First, calculate the square root of the stopping distance using the formula: $\sqrt{\text{distance}} = 3.30 + 0.235 \times 65$. This equals 18.575. Then, square this result to find the stopping distance: $18.575^2 \approx 345.0$ feet.

The Model Predicted distance =3.30+0.235× speed \sqrt { \text { distance } } = 3.30 + 0.235 \times \text { speed } distance ​=3.30+0.235× speed

The Model Predicted $\sqrt { \text { distance } } = 3.30 + 0.235 \times \text { speed }$