A manufacturer of cable wire periodically selects samples to monitor the process.A sample of ten wires is selected and the diameters (in cm.) are 0.493, 0.534, 0.527, 0.511, 0.565, 0.559, 0.519, 0.562, 0.551, and 0.530.The standard deviation is ________________________ .
A)0.455 cm
B)0.005 cm
C)0.045 cm
D)0.024 cm
E)0.099 cm

Question

Quizplus · Accepted Answer

The standard deviation is a measure of the spread of the data. The larger the standard deviation, the more spread out the data is. The standard deviation is calculated by taking the square root of the variance. The variance is calculated by taking the sum of the squared differences between each data point and the mean, and then dividing by the number of data points minus one. In this case, the mean is 0.535 cm. The variance is 0.0024 cm^2. The standard deviation is the square root of 0.0024 cm^2, which is 0.049 cm.

A Manufacturer of Cable Wire Periodically Selects Samples to Monitor