Solve the equation.
-$$e ^ { 2 x - 1 } = \left( e ^ { 6 } \right) ^ { - x }$$
A) $\left\{ \frac { 7 } { 3 } \right\}$
B) $\{ 0 \}$
C) $\left\{ \frac { 1 } { 8 } \right\}$
D) $\left\{ - \frac { 1 } { 4 } \right\}$

Question

Quizplus · Accepted Answer

The Answer of Solve the equation.
-$$e ^ { 2 x - 1 } = \left( e ^ { 6 } \right) ^ { - x }$$
A) $\left\{ \frac { 7 } { 3 } \right\}$
B) $\{ 0 \}$
C) $\left\{ \frac { 1 } { 8 } \right\}$
D) $\left\{ - \frac { 1 } { 4 } \right\}$

Solve the Equation e2x−1=(e6)−xe ^ { 2 x - 1 } = \left( e ^ { 6 } \right) ^ { - x }e2x−1=(e6)−x

Solve the Equation $e ^ { 2 x - 1 } = \left( e ^ { 6 } \right) ^ { - x }$