Suppose f(x) $f ( x ) = 28.9 + 1.5 \log ( x + 1 )$ odels salinity of ocean water to depths of 1000 meters at a certain latitude. x is the depth in meters and f(x) is in grams of salt per kilogram of seawater. Approximate the salinity (to the
Nearest hundredth) when the depth is 572 meters.
A) 81.21 g/kg
B) 78.21 g/kg
C) -24.76 g/kg
D) 33.04 g/kg

Question

Quizplus · Accepted Answer

To find the salinity at 572 meters, substitute x = 572 into the given function: $f(572) = 28.9 + 1.5 \log(572 + 1)$. Calculate the value inside the logarithm first, which is 573, then find the logarithm of 573, multiply by 1.5, and finally add 28.9 to get the result, which is approximately 33.04 grams of salt per kilogram of seawater.

Suppose F(x) f(x)=28.9+1.5log⁡(x+1)f ( x ) = 28.9 + 1.5 \log ( x + 1 )f(x)=28.9+1.5log(x+1)

Suppose F(x) $f ( x ) = 28.9 + 1.5 \log ( x + 1 )$