Factor the trinomial, if possible.
-$2 x ^ { 2 } - 12 x + 16$
A) $2 ( x - 2 ) ( x - 4 )$
B) $2 ( x - 8 ) ( x + 1 )$
C) $( x - 2 ) ( 2 x - 8 )$
D) $( 2 x - 4 ) ( x - 4 )$

Question

Quizplus · Accepted Answer

The trinomial $2x^2 - 12x + 16$ can be factored by first factoring out the greatest common factor, which is 2, resulting in $2(x^2 - 6x + 8)$. Then, the quadratic $x^2 - 6x + 8$ can be factored into $(x - 2)(x - 4)$, leading to the final factorization of $2(x - 2)(x - 4)$.

Factor the Trinomial, If Possible 2x2−12x+162 x ^ { 2 } - 12 x + 162x2−12x+16

Factor the Trinomial, If Possible $2 x ^ { 2 } - 12 x + 16$