Find or investigate the function as requested.
-If water is added to an empty tank such that the water level rises by 2 cm every 25 minutes, then what is the level of the water L(t)in the tank after t minutes?
A) $\mathrm { L } ( \mathrm { t } ) = \frac { 25 } { 2 } \mathrm { t }$
B) $L ( t ) = 2 t$
C) $\mathrm { L } ( \mathrm { t } ) = 50 \mathrm { t }$
D) $\mathrm { L } ( \mathrm { t } ) = \frac { 2 } { 25 } \mathrm { t }$

Question

Find or investigate the function as requested.
-If water is added to an empty tank such that the water level rises by 2 cm every 25 minutes, then what is the level of the water L(t)in the tank after t minutes? 
A) $\mathrm { L } ( \mathrm { t } ) = \frac { 25 } { 2 } \mathrm { t }$
B) $L ( t ) = 2 t$
C) $\mathrm { L } ( \mathrm { t } ) = 50 \mathrm { t }$
D) $\mathrm { L } ( \mathrm { t } ) = \frac { 2 } { 25 } \mathrm { t }$

Quizplus · Accepted Answer

The water level rises by 2 cm every 25 minutes, so the rate of increase is $2/25$ cm per minute. Therefore, the level of the water $L(t)$ after $t$ minutes is $L(t) = \frac{2}{25}t$.

Find or Investigate the Function as Requested L(t)=252t\mathrm { L } ( \mathrm { t } ) = \frac { 25 } { 2 } \mathrm { t }L(t)=225​t

Find or Investigate the Function as Requested $\mathrm { L } ( \mathrm { t } ) = \frac { 25 } { 2 } \mathrm { t }$