Solved

Solve the Inequality, Giving Its Solution Set in Both Interval $\frac { 8 x + 3 } { 8 } < \frac { 61 } { 8 }$

Question 220

Multiple Choice

Solve the inequality, giving its solution set in both interval and graph forms.
- $\frac { 8 x + 3 } { 8 } < \frac { 61 } { 8 }$
$Solve the inequality, giving its solution set in both interval and graph forms. - \frac { 8 x + 3 } { 8 } < \frac { 61 } { 8 } A) \left( - \infty , \frac { 29 } { 4 } \right) B) \left( - \infty , \frac { 61 } { 8 } \right) C) \left( \frac { 29 } { 4 } , \infty \right) D) \left( \frac { 61 } { 8 } , \infty \right)$

A) $\left( - \infty , \frac { 29 } { 4 } \right)$
$Solve the inequality, giving its solution set in both interval and graph forms. - \frac { 8 x + 3 } { 8 } < \frac { 61 } { 8 } A) \left( - \infty , \frac { 29 } { 4 } \right) B) \left( - \infty , \frac { 61 } { 8 } \right) C) \left( \frac { 29 } { 4 } , \infty \right) D) \left( \frac { 61 } { 8 } , \infty \right)$
B) $\left( - \infty , \frac { 61 } { 8 } \right)$
$Solve the inequality, giving its solution set in both interval and graph forms. - \frac { 8 x + 3 } { 8 } < \frac { 61 } { 8 } A) \left( - \infty , \frac { 29 } { 4 } \right) B) \left( - \infty , \frac { 61 } { 8 } \right) C) \left( \frac { 29 } { 4 } , \infty \right) D) \left( \frac { 61 } { 8 } , \infty \right)$
C) $\left( \frac { 29 } { 4 } , \infty \right)$
$Solve the inequality, giving its solution set in both interval and graph forms. - \frac { 8 x + 3 } { 8 } < \frac { 61 } { 8 } A) \left( - \infty , \frac { 29 } { 4 } \right) B) \left( - \infty , \frac { 61 } { 8 } \right) C) \left( \frac { 29 } { 4 } , \infty \right) D) \left( \frac { 61 } { 8 } , \infty \right)$
D) $\left( \frac { 61 } { 8 } , \infty \right)$
$Solve the inequality, giving its solution set in both interval and graph forms. - \frac { 8 x + 3 } { 8 } < \frac { 61 } { 8 } A) \left( - \infty , \frac { 29 } { 4 } \right) B) \left( - \infty , \frac { 61 } { 8 } \right) C) \left( \frac { 29 } { 4 } , \infty \right) D) \left( \frac { 61 } { 8 } , \infty \right)$